How do you simplify #-3i(2-5i) - (7+i)#? Precalculus Complex Numbers in Trigonometric Form Multiplication of Complex Numbers 1 Answer sudheer22kumar May 11, 2016 # -(22 + 7i)# Explanation: #-3i(2-5i) - (7+i) = -6i + 15i^2 -7 - i# #= -7i + 15(-1) -7# #= -7i - 15 -7# #= -7i - 22# #or, -(22 + 7i)# Answer link Related questions How do I multiply complex numbers? How do I multiply complex numbers in polar form? What is the formula for multiplying complex numbers in trigonometric form? How do I use the modulus and argument to square #(1+i)#? What is the geometric interpretation of multiplying two complex numbers? What is the product of #3+2i# and #1+7i#? How do I use DeMoivre's theorem to solve #z^3-1=0#? How do I find the product of two imaginary numbers? How do you simplify #(2+4i)(2-4i)#? How do you multiply #(-2-8i)(6+7i)#? See all questions in Multiplication of Complex Numbers Impact of this question 1625 views around the world You can reuse this answer Creative Commons License