Question

What is the derivative of `f(x)=ln (x^2+2)`?

Answer 1

`(df)/dx=(2x)/(x^2+2)`

Explanation:

Derivative of `f(x)=ln(x^2+2)` can be found using chain formula,

as `f(x)=ln(g(x))` and `g(x)=(x^2+2)`

Hence, `(df)/dx=1/(x^2+2)xx2x=(2x)/(x^2+2)`