How do you factor completely #10x^2-14xy-15x+21y#?
1 Answer
May 12, 2016
Explanation:
Factor by grouping:
#10x^2-14xy-15x+21y#
#=(10x^2-14xy)-(15x-21y)#
#=2x(5x-7y)-3(5x-7y)#
#=(2x-3)(5x-7y)#
