Question

If a sample has a mass of `1.25 * 10^2` `g` and a volume of `51` `mL`, what is its density?

Answer 1

`rho~=2.5*g*mL^-1`

Explanation:

`"Density"="Mass"/"Volume"`

Here, `"Density "rho=(1.25xx10^2*g)/(51*mL)`, which operation gives an answer in `g*mL^-1`, as is required for a density measurement.