Question

How do you find the derivative of `y=arcsin(5x+5)`?

Answer 1

`(dy)/(dx)=5/(sqrt(1-(5x+5)^2)`

Explanation:

As `y-arcsin(5x+5)`, `siny=5x+5`

Taking derivative of both sides

`cosy(dy)/(dx)=5`

`(dy)/(dx)=5/cosy=5/(sqrt(1-sin^2y)`

= `5/(sqrt(1-(5x+5)^2)`