How do you simplify and find the excluded value of #(t^2-25)/(t^2+t-20)#?

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Answer 1 · 2016-05-15T01:37:00

Factor both the numerator and the denominator.

#=((t + 5)(t- 5))/((t + 5)(t - 4))#

#= ((cancel(t + 5))(t - 5))/((cancel(t + 5))(t - 4))#

#= (t - 5)/(t - 4)#

To find the excluded value, we must set the denominator to 0.

#t - 4 = 0#

#t = 4#

Therefore, we can state that #t!= 4#.

Hopefully this helps!