Question

How do you solve for w in `logw=1/2logx + logy`?

Answer 1

`w = x^2y`

Explanation:

`0 = 1/2logx + logy - logw`

`0 = logx^2 + logy - logw`

`0 = log((x^2 xx y)/w)`

`10^0 = (x^2y)/w`

`1 = (x^2y)/w`

`w = x^2y`

Hopefully this helps!