How do you write an equation in slope-intercept form for a line with (5,0) and has a slope of -2/3?

1 Answer

Find the y-intercept with the given slope and given point, to find the general equation of #y=(-2/3)x+10/3#

Explanation:

Slope -intercept form is expressed in the form:

#y=mx+b# where #m# is the slope and #b# is the y intercept.

We're given the slope as #-2/3#.

To find #b#, let's fill in the equation with what we know: the slope and a point (an #x# and associated #y# point#):

#0=(-2/3)5+b# (multiply the fraction by 5, then add it to both sides)

#b=10/3#

That give's the final answer as:

#y=(-2/3)x+10/3#