How do you factor #a² + 2ab + b² - x² - 6x - 9#? Algebra Polynomials and Factoring Factoring Completely 1 Answer A. S. Adikesavan May 20, 2016 #(a+b+x+3)(a+b-x-3)#. Explanation: Use #A^2-B^3=(A+B)(A-B)# The expression is #(a+b)^2-(x+3)^2# #(a+b+x+3)(a+b-x-3)#. Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 2112 views around the world You can reuse this answer Creative Commons License