Question

How do you factor completely `32a^4 - 162b^4`?

Answer 1

It is

#32a^4-162b^4=2*(16a^4-81b^4)= 2*((2a)^4-(3b)^4)=2*((2a)^2-(3b)^2)*((2a)^2+(3b)^2)= 2*(2a-3b)*(2a+3b)*((2a)^2+(3b)^2)#