How do you find the slope and intercept of $y = 3 x + 1$ $y=3x+1$ ?

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Answer 1 · 2016-05-24T16:42:00

$slope=3 ; y intercept=1 ; x intercept= - \frac{1}{3}$ $"slope=3 ; y intercept=1 ; x intercept="-1/3$

$The coefficient of term 'x' gives slope of line$ $"The coefficient of term 'x' gives slope of line"$

$s l o p e = 3$ $slope=3$

$for y intercept; we write x=0$ $"for y intercept; we write x=0 "$

$y = 3 \cdot 0 + 1 y = 1$ $y=3*0+1" "y=1$

$for x intercept; we write y=0$ $"for x intercept; we write y=0"$

$0 = 3 x + 13 x = - 1 x = - \frac{1}{3}$ $0=3x+1" "3x=-1" "x=-1/3$

How do you find the slope and intercept of y=3x+1 y=3x+1?