What is the vertex of # y= x^2 - 2x - 15#? Algebra Quadratic Equations and Functions Quadratic Functions and Their Graphs 1 Answer Binayaka C. May 26, 2016 Vertex is at #(1,-16)# Explanation: #y=x^2-2x-15 or y= (x-1)^2-16 # We know, equation of parabola in vertex form is #y=a(x-h)^2+k# where #(h,k)# is the vertex. So here the vertex is at #(1,-16)# graph{x^2-2x-15 [-40, 40, -20, 20]}[Ans] Answer link Related questions What are the important features of the graphs of quadratic functions? What do quadratic function graphs look like? How do you find the x intercepts of a quadratic function? How do you determine the vertex and direction when given a quadratic function? How do you determine the range of a quadratic function? What is the domain of quadratic functions? How do you find the maximum or minimum of quadratic functions? How do you graph #y=x^2-2x+3#? How do you know if #y=16-4x^2# opens up or down? How do you find the x-coordinate of the vertex for the graph #4x^2+16x+12=0#? See all questions in Quadratic Functions and Their Graphs Impact of this question 4999 views around the world You can reuse this answer Creative Commons License