Question

How do you express `cos(pi/ 3 ) * sin( ( 5 pi) / 6 )` without using products of trigonometric functions?

Answer 1

`(1/2)sin (pi/6)`

Explanation:

`P = cos (pi/3).sin ((5pi)/6)`
Trig table -->
`cos (pi/3) = 1/2`
Unit circle, property of supplementary arcs -->
`sin ((5pi)/6) = sin (pi - pi/6) = sin (pi/6)`
P can be expressed as:
`P = (1/2)sin (pi/6)`