How do you solve #at+b=ar-c# for a?

1 Answer

combine the a terms on one side and all the other terms on the other to get to #-(c+b)/(t-r)#

Explanation:

Start with the original:

#at+b=ar-c#

Let's combine the terms with #a# on the left side and everything else on the right, so we'll subtract #ar# from both sides and subtract b from both sides:

#at-ar=-c-b#

We can now factor out a:

#a(t-r)=-c-b#

And now divide by (t-r) to solve for a:

#a=(-c-b)/(t-r)=((-(c+b))/(t-r))=-(c+b)/(t-r)#