How do you graph #ln(4-x)#?

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Answer 1 · 2016-05-30T20:40:29

Dee explanantion

set #ln(4-x)=y#

Build a table listing a selection of positive and negative values for #x#

For each value of #x# calculate the value of #y# and record that in your table

Mark the #(x,y)# points and as best as you can draw a freehand curve that passes through your marked points.

I usually use Excel to build table examples but for some reason it is not working.

Do not forget that if #x<0#, say -3 for example then

#y=ln(4-x) " "->" " y=ln[4-(-3)] " "->" " y=ln(4+3)#

Your graph should look something like this:
Tony B