Question

How do you convert `r=2sin(theta)` into cartesian form?

Answer 1

`x^2+y^2-2y=0`

Explanation:

`(x, y)=(r cos theta, r sin theta). r`2=x^2+y^2#.

So, `r^2=2r sin theta`. In cartesian form, this is

`x^2+y^2-2y=0`

This can be stardized to the form

`(x-0)^2+(y-1)^2=1` representing the circle with

center C(0, 1) and radius 1 unit.