Question

How do you convert `y=x` into polar form?

Answer 1

The polar representation of straight `y = x` is `theta = pi/4 + pi k` with `k = 1,2,3,...`

Explanation:

The pass equations are

#{ (x = r cos(theta)), (y = r sin(theta)) :}#

then

`r cos(theta) = r sin(theta)` or `tan(theta) = 1`

Solving for `theta` we have `theta = pi/4 + pi k` with `k = 1,2,...`

The polar representation of straight `y = x` is `theta = pi/4 + pi k` with `k = 1,2,3,...`