How do you find the inverse of #f(x)=sqrt(x+1) + 3# and is it a function?

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Answer 1 · 2016-06-05T02:47:50

The inverse of a function can be found algebraically by switching the x and y values.

#y = sqrt(x + 1) + 3#

#x = sqrt(y + 1) + 3#

#x - 3 = sqrt(y + 1)#

#(x - 3)^2 = (sqrt(y + 1))^2#

#x^2 - 6x + 9 = y + 1#

#x^2 - 6x + 8 = y#

This is a quadratic, therefore it is a function.

Hopefully this helps!