How do you factor #4azc² - 8azc + 4az#?
1 Answer
Jun 6, 2016
#4az(c-1)(c-1)#
Explanation:
#4azc^2-8azc+4az#
#4az(c^2-2c+1)#
#4az(c^2-c-c+1)#
#4az(c(c-1)-1(c-1))#
#4az(c-1)(c-1)#
