Question

A gas occupies 11.2 liters at .860 atm. What is the pressure if the volume becomes 15.0 L?

Answer 1

`P_1V_1` `=` `P_2V_2" at constant "T`. Boyle's Law

Explanation:

`P_2` `=` `(P_1V_1)/V_2` `=` `(0.860*atmxx11.2*cancelL)/(15.0*cancelL)` `~=0.6*atm`.

Boyle's Law is useful in that given non-standard units, it can still be used provided that the units are consistent,