Question

How do you solve `3log_3 4a=3`?

Answer 1

`log_3(4a)^3 = 3`

Use the rule `alogn = logn^a`

`log_3(64a^3) = 3`

Recall that if `log_a(n) = x`, then `a^x = n`

`64a^3 = 27`

`a^3 = 27/64`

`a = root(3)(27/64)`

`a = 3/4`

Hopefully this helps!