Question

How do you factor `16x^4-81`?

Answer 1

`(4x^2+9)(2x+3)(2x-3)`

Explanation:

`16 x^4 -81 = (4x^2)^2 -(3^2) = (4x^2 +9)(4x^2-9) =(4x^2+9)(2x+3)(2x-3)` [Ans]