How do you differentiate #f(x)=e^tan(1-x^2) # using the chain rule? Calculus Basic Differentiation Rules Chain Rule 1 Answer Trevor Ryan. Jun 10, 2016 #d/dxe^(tan(1-x^2))= -2xsec^2(1-x^2)e^(tan(1-x^2))# Explanation: #d/dxe^(tan(1-x^2))=e^(tan(1-x^2)) * sec^2(1-x^2) * (-2x)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1729 views around the world You can reuse this answer Creative Commons License