Question

Exactly 5.00 L of air at -50.0°C is warmed to 100.0°C. What is the new volume if the pressure remains constant?

Answer 1

Given your reaction conditions, your volume of gas is in a piston. The gas should expand to a `~=8*L` volume.

Explanation:

I think you have asked this question before; it is still suspect because we must assume that the gas is enclosed in a container whose volume can change, i.e. a piston.

Charles' Law states that `"Volume "prop" Temperature"`, i.e. `VpropT`, or `V=kT`.

Solving for `k`, `V_1/T_1=V_2/T_2`, and here we must use `" Absolute Temperature"` `=` `""^@C + 273.15*K`.

`V_2=(V_1T_2)/T_1` `=` `(5.00*Lxx373.15*K)/(223.15*K)` `=` `??L`