Exactly 5.00 L of air at -50.0°C is warmed to 100.0°C. What is the new volume if the pressure remains constant?

1 Answer
Jun 12, 2016

Given your reaction conditions, your volume of gas is in a piston. The gas should expand to a ~=8*L volume.

Explanation:

I think you have asked this question before; it is still suspect because we must assume that the gas is enclosed in a container whose volume can change, i.e. a piston.

Charles' Law states that "Volume "prop" Temperature", i.e. VpropT, or V=kT.

Solving for k, V_1/T_1=V_2/T_2, and here we must use " Absolute Temperature" = ""^@C + 273.15*K.

V_2=(V_1T_2)/T_1 = (5.00*Lxx373.15*K)/(223.15*K) = ??L