How do you simplify #[4 - (3)(-10)] [(-8) div (6-2)]#? Prealgebra Fractions Equivalent Fractions and Simplifying 1 Answer Shwetank Mauria Jun 13, 2016 #[4-(3)(-10)][(-8)-:(6-2)]=-68# Explanation: #[4-(3)(-10)][(-8)-:(6-2)]# = #[4-(-3xx10)][(-8)-:4]# = #[4-(-30)] (-8/4)# = #(4+30) (-2)# = #34xx(-2)# = #-68# Answer link Related questions What is 0.098 divided by 7? How do you find the fraction notation and simplify 16.6%? How do you convert #0.bar(45)# (meaning the #45# is being repeated) to a fraction? How do you convert 0.40 (40 repeating) to a fraction? How do you convert 8/15 to a decimal? How do you express #3/4, 7/16,# and #5/8# with the #LCD#? How do you simplify fractions? What is the simplified form of #30/42#? How do you subtract and simplify #9-5 1/3#? How do you add and simplify #5/7 + 3/4#? See all questions in Equivalent Fractions and Simplifying Impact of this question 1915 views around the world You can reuse this answer Creative Commons License