Question

What is the distance between `(–4, 0, 2)` and #(2, –3, 1) #?

Answer 1

distance=`sqrt(46)`

Explanation:

Use the distance formula:
`d=sqrt((x2-x1)^2+(y2-y1)^2-(z2-z1)^2`

`d=sqrt((2+4)^2+(-3-0)^2+(1-2)^2`

`d=sqrt(36+9+1)`

`d=sqrt(46)`