Question

How do you differentiate given `sin^2(x/6)`?

Answer 1

`(df)/(dx)=sin(x/3)`

Explanation:

As `f(x)=sin^2(x/6)`

Using chain rule, `(df)/(dx)=2sin(x/6)xxcos(x/6)`

Now as `2sinAcosA=sin2A`,

`(df)/(dx)=sin(x/3)`