How do you find the period of $f (x) = 3 sin (\frac{x}{2} + π)$ $f(x) = 3sin (x/2 + pi)$ ?

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How do you find the period of $f (x) = 3 sin (\frac{x}{2} + π)$ $f(x) = 3sin (x/2 + pi)$ ?

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Answer 1 · 2016-06-17T12:34:48

period $= 4 π$ $=4pi$

Explanation:

The standard form of the sine wave function is

$y = a sin (b x + c) + d$ $y=asin(bx+c)+d$

where amplitude $= | a |$ $= |a|$ , period $= \frac{2 π}{b}$ $=(2pi)/b$

phase shift $= - \frac{c}{b} and d , the vertical shift$ $=-c/b" and d , the vertical shift"$

here $b = \frac{1}{2} \Rightarrow period = \frac{2 π}{\frac{1}{2}} = 4 π$ $b=1/2rArr" period"=(2pi)/(1/2)=4pi$

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How do you find the period of $f (x) = 3 sin (\frac{x}{2} + π)$ $f(x) = 3sin (x/2 + pi)$ ?

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How do you find the period of $f (x) = 3 sin (\frac{x}{2} + π)$ $f(x) = 3sin (x/2 + pi)$ ?