What is the derivative of #f(x)=e^(2x) ln(x+2)#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Shwetank Mauria Jun 18, 2016 #(df)/(dx)=e^(2x)(2ln(x+2)+1/(x+2))# Explanation: As #f(x)=e^(2x)xxln(x+2)# #(df)/(dx)=e^(2x)xx2xxln(x+2)+e^(2x)xx1/(x+2)# = #e^(2x)(2ln(x+2)+1/(x+2))# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 3216 views around the world You can reuse this answer Creative Commons License