Question

How do you find the derivative of `(x/(2x+1))`?

Answer 1

`(df)/(dx)=1/(2x+1)^2`

Explanation:

Quotient rule states if `f(x)=(g(x))/(h(x))`

then `(df)/(dx)=((dg)/(dx)xxh(x)-(dh)/(dx)xxg(x))/(h(x))^2`

As `f(x)=x/(2x+1)`

`(df)/(dx)=(1xx(2x+1)-2xx x)/(2x+1)^2=1/(2x+1)^2`