Question

How do you differentiate the following parametric equation: `x(t)=t-cos2t, y(t)=tsin^2t`?

Answer 1

`x'(t)=1+sin2t*2` `=1+2sin2t`
`y'(t)=sin^2t+t*2costsint`

Explanation:

`d/dx-cos2t=-(-sin2t)*2=2sin2t`

`x'(t)=1+sin2t*2` `=1+2sin2t`

`d/dxsin^2t=d/dx(sint*sint)=2costsint`

`y'(t)=sin^2t+t*2costsint`