Question

What is the period of `f(theta) = tan ( ( 13 theta)/12 )- cos ( ( 3 theta)/ 4 )`?

Answer 1

`24pi`

Explanation:

Period of `tan ((13t)/12)` --> `(12pi)/13`
Period of `cos ((3t)/4)` --> `(8pi)/3`
Period of f(t) --> least common multiple of `(12pi)/13` and `(8pi)/3`

`(12pi)/13` ...x ..(26) ...--> `24pi`
`(8pi)/3` ...x...(9)....---> `24pi`
Period of f(t) --> `24pi`