How do you simplify the expression 2^5/(2^3 times 2^8)? Prealgebra Exponents, Radicals and Scientific Notation Exponents 1 Answer Shwetank Mauria Jun 21, 2016 2^5/(2^3xx2^8)=1/2^6 Explanation: 2^5/(2^3xx2^8) = 2^5/(2^3xx2^(3+5)) = 2^5/(2^3xx2^3xx2^5) = (1cancel2^5)/(2^3xx2^3xxcancel2^5) = 1/(2^3xx2^3)=1/2^(3+3)=1/2^6 Answer link Related questions How do you simplify c^3v^9c^-1c^0? How do you simplify (- 1/5)^-2 + (-2)^-2? How do you simplify (4^6)^2 ? How do you simplify 3x^(2/3) y^(3/4) (2x^(5/3) y^(1/2))^3 ? How do you simplify 4^3·4^5? How do you simplify (5^-2)^-3? How do you simplify and write (-5.3)^0 with positive exponents? How do you factor 12j^2k - 36j^6k^6 + 12j^2? When can I add exponents? What is the Zero Exponent Rule? See all questions in Exponents Impact of this question 3604 views around the world You can reuse this answer Creative Commons License