Question

How do you differentiate the following parametric equation: `x(t)=t^2+cos2t, y(t)=t-sint`?

Answer 1

`\frac{dy}{dx} = \frac{1 - cos t}{2(t - sin 2t)}`

Explanation:

`\frac{dx}{dt} = 2t - 2 sin 2t`

`\frac{dy}{dt} = 1 - cos t`

`\frac{dy}{dx} = \frac{\frac{dy}{dt}}{\frac{dx}{dt}} = \frac{1 - cos t}{2(t - sin 2t)}`