How do you solve and write the following in interval notation: #3>= 7-x/2 >=1#?

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Answer 1 · 2016-06-21T12:04:42

#x in [8;12]#

It is useful to multiply all terms by 2 to eliminate fractions:

#6>=14-x>=2#

and then you can subtract 14:

#6-14>=-x>=2-14#

#-8>=-x>=-12#

that's equivalent to:

#8<=x<=12#