Question

The nut below has a density of 4 g/mL and a mass of 12 g. What is the volume of the nut?

Answer 1

`"Density "rho` `=` `"Mass"/"Volume"`

Explanation:

We has `rho`, and we have `"mass"`.

And thus `"Volume"` is the quotient `"Mass"/rho`

`=` `(12*cancelg)/(4*cancelg*mL^-1)` `=` `??*mL`.

Note that the inclusion of units is an extra check on our calculations. We sought a volume; the answer we got had units of volume, i.e. `1/((mL)^-1)=1/(1/(mL))=mL`.

This is a good indication that we are on the right track and have not made an error.