A solid consists of a cone on top of a cylinder with a radius equal to that of the cone. The height of the cone is #21 # and the height of the cylinder is #7 #. If the volume of the solid is #42 pi#, what is the area of the base of the cylinder?

Question

1405 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-06-27T01:49:56

#3pi#

Assume the radius of the cylinder/cone as r, height of cone as #h_1#, height of cylinder as #h_2#

Volume of the cone part of solid = #(pi*r^2*h_1)/3#

Volume of the cylinder part of solid = # pi*r^2 * h_2#

What we have is:

#h_1# = 21,#h_2# = 7

#(pi*r^2*h_1)/3# + # pi*r^2 * h_2# = #42*pi#

#(pi*r^2*21)/3# + # pi*r^2 * 7# = #42*pi#

# pi*r^2 * 7# + # pi*r^2 * 7# = #42*pi#

# pi*r^2 * 14# = #42*pi#

# r^2 # = #42/14# = 3

Area of the base of the cylinder = #pi*r^2# = #pi*3# = #3pi#