A solid consists of a cone on top of a cylinder with a radius equal to that of the cone. The height of the cone is #18 # and the height of the cylinder is #1 #. If the volume of the solid is #84 pi#, what is the area of the base of the cylinder?

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Answer 1 · 2016-06-27T02:59:17

#12pi#

Assume the radius of the cylinder/cone as r, height of cone as #h_1#, height of cylinder as #h_2#

Volume of the cone part of solid = #(pi*r^2*h_1)/3#

Volume of the cylinder part of solid = # pi*r^2 * h_2#

What we have is:

#h_1# = 18,#h_2# = 1

#(pi*r^2*h_1)/3# + # pi*r^2 * h_2# = #84*pi#

#(pi*r^2*18)/3# + # pi*r^2 * 1# = #84*pi#

# pi*r^2 * 6# + # pi*r^2 * 1# = #84*pi#

# pi*r^2 * 7# = #84*pi#

# r^2 # = #84/7# = 12

Area of the base of the cylinder = #pi*r^2# = #pi*12# = #12pi#