How do you factor completely #5a-15a^2#?
1 Answer
Jun 28, 2016
5a(1-3a)
Explanation:
There is a common factor of 5a in both terms which can be 'taken out'.
#rArr5a-15a^2=5a(1-3a)# This may be checked by distributing the bracket.
#5a(1-3a)=(5axx1)-(5axx3a)=5a-15a^2#
