Question

How do you find the slope that is perpendicular to the line `x + 3y = 5`?

Answer 1

Slope of line perpendicular to `x+3y=5` is `3`

Explanation:

The product of slopes of two lines perpendicular to each other is `-1`.

To find the slope of line `x+3y=5`, let us convert it into slope intercept from `y=mx+c`, where `m` is the slope of line and `c` is its intercept on `y`-axis.

As `x+3y=5`, we have `3y=-x+5` or

`y=-1/3x+5/3`

Hence slope of `x+3y=5` is `-1/3` and

slope of line perpendicular to it will be `(-1)/(-1/3)=1/(1/3)=3`