If one of the terms of the binomial expression #(x+y-3z)^n# is #A*x^3*y^4*z^2# , what is #n# ? Precalculus The Binomial Theorem Pascal's Triangle and Binomial Expansion 1 Answer Cesareo R. Jul 1, 2016 #n = 9# and #A = 11340# Explanation: In #(x+y-3z)^9# appears all the #x^ay^bz^c# products such that #a+b+c=9# Answer link Related questions What is Pascal's triangle? How do I find the #n#th row of Pascal's triangle? How does Pascal's triangle relate to binomial expansion? How do I find a coefficient using Pascal's triangle? How do I use Pascal's triangle to expand #(2x + y)^4#? How do I use Pascal's triangle to expand #(3a + b)^4#? How do I use Pascal's triangle to expand #(x + 2)^5#? How do I use Pascal's triangle to expand #(x - 1)^5#? How do I use Pascal's triangle to expand a binomial? How do I use Pascal's triangle to expand the binomial #(a-b)^6#? See all questions in Pascal's Triangle and Binomial Expansion Impact of this question 1668 views around the world You can reuse this answer Creative Commons License