Question

What is the derivative of this function `x^2 sin(1/x) - 2`?

Answer 1

`f'(x)=2x*sin(1/x)-cos(1/x)`

Explanation:

Let `f(x)=x^2sin(1/x)-2`.
`:. f'(x)=x^2*d/dxsin(1/x)+sin(1/x)*d/dxx^2`.
`=x^2*cos(1/x)*d/dx(1/x)+2x*sin(1/x)`
`=x^2*cos(1/x)*(-1/x^2)+2x*sin(1/x)`
`=2x*sin(1/x)-cos(1/x)`