How do you factor #81x^5y+24x^2y^4#?

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Answer 1 · 2016-07-02T22:50:47

#3x^2y(3x+2y)(9x^2 - 6xy +4y^2)#

Always look for a common factor first, in this case, #3x^2y#

#3x^2y(27x^3 + 8y^3) " now this is the sum of cubes"#

=#3x^2y(3x+2y)(9x^2 - 6xy +4y^2)#

Sum of cubes is given as:

#(x^3 + y^3) = (x+y)(x^2 - xy + y^2)#

Difference of cubes is given as:

#(x^3 - y^3) = (x-y)(x^2 + xy + y^2)#