How do you solve #13x + 26 < 65#?

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Answer 1 · 2016-07-03T22:30:29

#x <3#

What I would do is subtract 26 to both sides of the expression to cancel out the 26 on the left side and to get 13x by itself like this:

#13x + 26 < 65#
# -26 -26#

When you do that you should get

#13x < 39#

Now divide both sides by 13 to get x by itself like this:

#(13x)/13 < 39/13#

When you do that division you're left with x on the left hand side and 3 on the right hand side, with a less than sign separating them like this:

#x <3#