Question

Find the value of `(secx-1)(secx+1)` and `1-sin^2theta/tan^2theta`?

Answer 1

`(secx-1)(secx+1)=tan^2x` and `1-sin^2theta/tan^2theta=sin^2theta`

Explanation:

`(secx-1)(secx+1)=sec^2x-1=1+tan^2x-1=tan^2x`

`1-sin^2theta/tan^2theta=1-sin^2theta/(sin^2theta/cos^2theta)`

= `1-sin^2thetaxxcos^2theta/sin^2theta`

= `1-cos^2theta`

= `sin^2theta`