Question

A projectile is shot from the ground at a velocity of `3 m/s` and at an angle of `(7pi)/12`. How long will it take for the projectile to land?

Answer 1

`0.0196s`

Explanation:

The equation to find time of flight given angle and speed of launch is:
`t=(2v_osin(theta))/g`
where:
`t` is the time taken to hit the ground
`v_o` is the launch speed of the projectile (`3ms^-1)`
`theta` is the angle of launch (`(7pi)/12`)
`g` is the acceleration due to gravity (`9.81ms^-1`)

We then substitute these values into the equation

`t=(2(3ms^-1)sin((7pi)/12))/(9.81ms^-1`)`

`t=0.01955s = 0.0196s" (3 s.f.")`

For more projectile motion formulas look here.