The density of gold is 19.3 g/mL. What volume (in mL) will a 1.592 lb sample of gold occupy?

1 Answer
anor277
Jul 7, 2016

Volume occupied is approx. #38*mL#

Explanation:

#"Density "rho# #=# #"Mass"/"Volume"#

And thus #"Volume"# #=# #"Mass"/rho# #=# #(1.592*lbxx454*g*lb^-1)/(19.3*g*mL^-1)# #=# #??*mL#

It doesn't seem a very big nugget does it? Nevertheless, the nugget would be worth over #$30000*USD#.

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