Question

How do you convert `[-6,3pi/2]` to rectangular form?

Answer 1

Rectangular form is `(0,6)`

Explanation:

Polar coordinates are given as follows: `(r, theta)`.

From the given problem, `r=-6, theta=(3pi)/2`

We can use the following formulas to get our x and y values:
`x = rcostheta, y=rsintheta`

`x = rcostheta = -6cos(3pi)/2 = -6 * 0 = 0`

`y = rsintheta = -6sin(3pi)/2 = -6 * -1 = 6`

Therefore, our coordinate is `(0,6)`