Question

How do you combine `6/(5a^2b)-1/(10ab)`?

Answer 1

`6/(5a^2b)-1/(10ab)=(12-a)/(10a^2b)`

Explanation:

We have `5a^2b=5×a×a×b` and `10ab=2×5×a×b` in denominator. Their GCD is `2×5×a×a×b=10a^2b`.

Hence `6/(5a^2b)-1/(10ab)`

= `(6×2)/(5a^2b×2)-(1×a)/(10ab×a)`

= `12/10a^2b-a/(10a^2b)`

= `(12-a)/(10a^2b)`