Question

How do you write an equation of a line given point (-2,5/2) and slope -1/2?

Answer 1

`y=-1/2x+3/2`

Explanation:

You can use the general equation:

`y-y_0=m(x-x_0)`

where the point `(x_0,y_0)` will be substituted by `(-2,5/2)`
and m is the slope `-1/2`

So your equation will be:

`y-5/2=-1/2(x+2)`

`y=-1/2x-1+5/2`

`y=-1/2x+3/2`